Key points are not available for this paper at this time.
Let S₀ be any sequential probability ratio test for deciding between two simple alternatives H₀ and H₁, and S₁ another test for the same purpose. We define (i, j = 0, 1): ᵢ (Sⱼ) = probability, under Sⱼ, of rejecting Hᵢ when it is true; Eᵢʲ (n) = expected number of observations to reach a decision under test Sⱼ when the hypothesis Hᵢ is true. (It is assumed that E¹ᵢ (n) exists. ) In this paper it is proved that, if ᵢ (S₁) ᵢ (S₀) (i = 0, 1), it follows that Eᵢ⁰ (n) Eᵢ¹ (n) (i = 0, 1). This means that of all tests with the same power the sequential probability ratio test requires on the average fewest observations. This result had been conjectured earlier (1, 2).
Building similarity graph...
Analyzing shared references across papers
Loading...
Abraham Wald
J. Wolfowitz
The Annals of Mathematical Statistics
Building similarity graph...
Analyzing shared references across papers
Loading...
Wald et al. (Wed,) studied this question.
www.synapsesocial.com/papers/69de855afd84e72eb25587a5 — DOI: https://doi.org/10.1214/aoms/1177730197