We resolve the strong CP problem: θQCD = 0 exactly because the strong force is an even (k=2) mode of the pentagon, preserving D₅ reflection symmetry. The weak force (k=3, odd) breaks reflections, explaining CP violation. No axion needed.
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Pei-Yuan Ju (Sat,) studied this question.
www.synapsesocial.com/papers/69ada962bc08abd80d5bca19 — DOI: https://doi.org/10.5281/zenodo.18899301
Pei-Yuan Ju
Taipei City Government
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